2a+3a=a^2+40

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Solution for 2a+3a=a^2+40 equation: 



2a+3a=a^2+40

We move all terms to the left:

2a+3a-(a^2+40)=0

We add all the numbers together, and all the variables

5a-(a^2+40)=0

We get rid of parentheses

-a^2+5a-40=0

We add all the numbers together, and all the variables

-1a^2+5a-40=0

a = -1; b = 5; c = -40;
Δ = b2-4ac
Δ = 52-4·(-1)·(-40)
Δ = -135
Delta is less than zero, so there is no solution for the equation

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